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JEE Main & Advanced Chemistry Solutions / विलयन Question Bank Elevation of boiling point of the solvent

  • question_answer
    Elevation in boiling point was \[{{0.52}^{o}}C\] when \[6\,gm\] of a compound \[X\] was dissolved in \[100\,gm\] of water. Molecular weight of \[X\] is \[({{K}_{b}}\] for water is 0.52 per 1000 gm of water) [CPMT 1989]

    A)                 120        

    B)                 60

    C)                 180        

    D)                 600

    Correct Answer: B

    Solution :

                  \[\Delta {{T}_{b}}=\frac{100\times {{K}_{b}}\times w}{m\times W}\]   \ \[0.52=\frac{100\times 5.2\times 6}{m\times 100}\]                                 \[m=\frac{100\times 5.2\times 6}{0.52\times 100}=60\].         


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