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JEE Main & Advanced Mathematics Conic Sections Question Bank Ellipse

  • question_answer
    The distance between the foci of the ellipse \[3{{x}^{2}}+4{{y}^{2}}=48\] is

    A)            2     

    B)            4

    C)            6     

    D)            8

    Correct Answer: B

    Solution :

               \[\frac{{{x}^{2}}}{(48/3)}+\frac{{{y}^{2}}}{(48/4)}=1\]                    \[{{a}^{2}}=16,\ {{b}^{2}}=12\] Þ \[e=\sqrt{1-\frac{{{b}^{2}}}{{{a}^{2}}}}=\frac{1}{2}\]                    Distance is\[2ae=2\cdot 4\cdot \frac{1}{2}=4\].


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