A) \[\sqrt{3}x-y+7=0\]
B) \[\sqrt{3}x-y-7=0\]
C) \[\sqrt{3}x-y\pm 7=0\]
D) None of these
Correct Answer: C
Solution :
\[m=\tan 60{}^\circ =\sqrt{3}\]. Therefore, equation of tangent is \[y=\sqrt{3}x\pm \sqrt{1+3\cdot 16}\] Þ \[y=\sqrt{3}x\pm 7\].You need to login to perform this action.
You will be redirected in
3 sec