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JEE Main & Advanced Mathematics Conic Sections Question Bank Ellipse

  • question_answer
    The sum of the focal distances of any point on the conic \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\] is                                      [Karnataka CET 2005]

    A)            10   

    B)            9

    C)            41   

    D)            18

    Correct Answer: A

    Solution :

                       For any point P on the ellipse have focus S and S¢ \[SP+{S}'P=2a\]            \ For \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\]            Sum of focal distances = 2 ´ 5 = 10.


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