A) 2/5
B) 2/3
C) 4/5
D) 3/4
E) 3/5
Correct Answer: E
Solution :
\[25{{(x-3)}^{2}}+16{{y}^{2}}=400\] \[\frac{{{(x-3)}^{2}}}{16}+\frac{{{y}^{2}}}{25}=1\] \[e=\sqrt{1-\frac{16}{25}}=\frac{3}{5}\]
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