JEE Main & Advanced Mathematics Conic Sections Question Bank Ellipse

  • question_answer
    The equation of the ellipse whose vertices are \[(\pm 5,\ 0)\] and foci are \[(\pm 4,\ 0)\] is

    A)            \[9{{x}^{2}}+25{{y}^{2}}=225\] 

    B)            \[25{{x}^{2}}+9{{y}^{2}}=225\]

    C)            \[3{{x}^{2}}+4{{y}^{2}}=192\]   

    D)            None of these

    Correct Answer: A

    Solution :

               Vertices \[(\pm 5,\,0)\equiv (\pm a,\,0)\] Þ \[a=5\]            Foci \[(\pm 4,\,0)\equiv (\pm ae,\,0)\] Þ \[e=\frac{4}{5}\],  \ \[b=(5)\,\left( \frac{3}{5} \right)=3\] Hence equation is \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{9}=1\] i.e., \[9{{x}^{2}}+25{{y}^{2}}=225\].


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