A) 1/2
B) \[1/\sqrt{2}\]
C) 1/3
D) \[1/\sqrt{3}\]
Correct Answer: B
Solution :
Foci are \[(\pm ae,0)\]. Therefore according to the condition, \[2ae=2b\]or \[ae=b\] Also, \[{{b}^{2}}={{a}^{2}}(1-{{e}^{2}})\]Þ \[{{e}^{2}}=(1-{{e}^{2}})\]Þ \[e=\frac{1}{\sqrt{2}}\]
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