A) \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{25}=1\]
B) \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\]
C) \[\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{25}=1\]
D) None of these
Correct Answer: A
Solution :
Centre (0, 0), focus (0, 3), \[b=5\] Focus (0, 3) Þ \[be=3\]Þ \[e=3/5\] Þ \[a=b\sqrt{1-{{e}^{2}}}=4\] Hence the required equation is\[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{25}=1\].
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