JEE Main & Advanced Mathematics Conic Sections Question Bank Ellipse

  • question_answer
    hThe equation of the ellipse whose latus rectum is 8 and whose eccentricity is \[\frac{1}{\sqrt{2}}\], referred to the principal axes of coordinates, is [MP PET 1993]

    A)            \[\frac{{{x}^{2}}}{18}+\frac{{{y}^{2}}}{32}=1\]                            

    B)            \[\frac{{{x}^{2}}}{8}+\frac{{{y}^{2}}}{9}=1\]

    C)            \[\frac{{{x}^{2}}}{64}+\frac{{{y}^{2}}}{32}=1\]                            

    D)            \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{24}=1\]

    Correct Answer: C

    Solution :

               \[\frac{2{{b}^{2}}}{a}=8,\]\[e=\frac{1}{\sqrt{2}}\]Þ \[{{a}^{2}}=64,\,{{b}^{2}}=32\]            Hence required equation of ellipse is\[\frac{{{x}^{2}}}{64}+\frac{{{y}^{2}}}{32}=1\].


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