A) \[2x=\pm 25\]
B) \[5x=\pm 9\]
C) \[3x=\pm 10\]
D) None of these
Correct Answer: D
Solution :
\[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\] Þ \[e=\sqrt{1-\frac{16}{25}}=\frac{3}{5}\] Therefore, directrices are \[x\pm \frac{5}{3/5}=0\] or \[3x\pm 25=0\].You need to login to perform this action.
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