A) 2
B) 4
C) 6
D) 8
Correct Answer: B
Solution :
\[\frac{{{x}^{2}}}{(48/3)}+\frac{{{y}^{2}}}{(48/4)}=1\] \[{{a}^{2}}=16,\ {{b}^{2}}=12\] Þ \[e=\sqrt{1-\frac{{{b}^{2}}}{{{a}^{2}}}}=\frac{1}{2}\] Distance is\[2ae=2\cdot 4\cdot \frac{1}{2}=4\].You need to login to perform this action.
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