A) 3
B) \[4\sqrt{2}\]
C) 6
D) None of these
Correct Answer: D
Solution :
\[\frac{a}{e}-ae=8\]. Also \[e=\frac{1}{2}\]Þ \[a=\frac{8e}{(1-{{e}^{2}})}=\frac{8.4}{2(3)}=\frac{16}{3}\] \[\therefore b=\frac{16}{3}\sqrt{\left( 1-\frac{1}{4} \right)}=\frac{16}{3}\frac{\sqrt{3}}{2}=\frac{8\sqrt{3}}{3}\] Hence the length of minor axis is \[\frac{16\sqrt{3}}{3}\].You need to login to perform this action.
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