A) \[\frac{3}{4}\]
B) \[\frac{4}{3}\]
C) \[\frac{1}{\sqrt{7}}\]
D) \[\frac{{{x}^{2}}}{4}+{{y}^{2}}=1\]
Correct Answer: A
Solution :
\[{{e}^{2}}=1-\frac{{{b}^{2}}}{{{a}^{2}}}\]Þ\[{{e}^{2}}=\frac{36}{64}\]Þ \[e=\frac{3}{4}\].
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