A) 3/5
B) 1/3
C) 2/5
D) 1/5
Correct Answer: A
Solution :
\[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{25}=1\] \[\Rightarrow \,{{a}^{2}}={{b}^{2}}\,\,(1-{{e}^{2}})\] \[\Rightarrow \,{{e}^{2}}=1-\frac{16}{25}\,\,\,\Rightarrow \,e=3/5\].
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