A) \[\frac{4}{5}\]
B) \[\frac{1}{\sqrt{52}}\]
C) \[\frac{3}{5}\]
D) \[25{{x}^{2}}+144{{y}^{2}}=900\]
Correct Answer: C
Solution :
Distance between foci\[=6\]Þ \[ae=3\]. Minor axis \[=8\]Þ\[2b=8\]Þ\[b=4\]Þ\[{{b}^{2}}=16\] Þ\[{{a}^{2}}(1-{{e}^{2}})=16\]Þ\[{{a}^{2}}-{{a}^{2}}{{e}^{2}}=16\]Þ\[{{a}^{2}}-9=16\]Þa=5 Hence\[ae=3\]Þ \[e=\frac{3}{5}\].
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