JEE Main & Advanced Mathematics Conic Sections Question Bank Ellipse

  • question_answer
    Latus rectum of ellipse \[4{{x}^{2}}+9{{y}^{2}}-8x-36y+4=0\] is [MP PET 1989]

    A)            8/3 

    B)            4/3

    C)            \[\frac{\sqrt{5}}{3}\]                

    D)            16/3

    Correct Answer: A

    Solution :

               The ellipse is \[4{{(x-1)}^{2}}+9{{(y-2)}^{2}}=36\]            Therefore, latus rectum\[=\frac{2{{b}^{2}}}{a}=\frac{2.4}{3}=\frac{8}{3}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner