JEE Main & Advanced Mathematics Conic Sections Question Bank Ellipse

  • question_answer
    The equation of an ellipse whose focus (?1, 1), whose directrix is \[x-y+3=0\] and whose eccentricity is \[\frac{1}{2}\], is given by             [MP PET 1993]

    A)            \[7{{x}^{2}}+2xy+7{{y}^{2}}+10x-10y+7=0\]

    B)            \[7{{x}^{2}}-2xy+7{{y}^{2}}-10x+10y+7=0\]

    C)            \[7{{x}^{2}}-2xy+7{{y}^{2}}-10x-10y-7=0\]

    D)            \[7{{x}^{2}}-2xy+7{{y}^{2}}+10x+10y-7=0\]

    Correct Answer: A

    Solution :

               Let any point on it be (x, y), then \[\frac{\sqrt{{{(x+1)}^{2}}}+\sqrt{{{(y-1)}^{2}}}}{\left| \frac{x-y+3}{\sqrt{2}} \right|}=\frac{1}{2}\]                    Squaring and simplifying, we get                    \[7{{x}^{2}}+2xy+7{{y}^{2}}+10x-10y+7=0\].


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