A) \[\frac{5}{6}\]
B) \[\frac{3}{5}\]
C) \[\frac{\sqrt{2}}{3}\]
D) \[\frac{\sqrt{5}}{3}\]
Correct Answer: D
Solution :
\[4{{x}^{2}}+8x+4+9{{y}^{2}}+36y+36=36\] \[\Rightarrow \frac{{{(x+1)}^{2}}}{9}+\frac{{{(y+2)}^{2}}}{4}=1\]; \\[e=\sqrt{1-\frac{4}{9}}=\frac{\sqrt{5}}{3}\].
You need to login to perform this action.
You will be redirected in
3 sec
