A) (1, 2), (3, 4)
B) (1, 4), (3, 1)
C) (1, 1), (3, 1)
D) (2, 3), (5, 4)
Correct Answer: C
Solution :
\[3{{x}^{2}}-12x+4{{y}^{2}}-8y=-4\]Þ\[3{{(x-2)}^{2}}+4{{(y-1)}^{2}}=12\] Þ \[\frac{{{(x-2)}^{2}}}{4}+\frac{{{(y-1)}^{2}}}{3}=1\] Þ \[\frac{{{X}^{2}}}{4}+\frac{{{Y}^{2}}}{3}=1\] \ \[e=\sqrt{1-\frac{3}{4}}=\frac{1}{2}\]. \ Foci are \[\left( X=\pm 2\times \frac{1}{2},\,Y=0 \right)\] i.e., \[(x-2=\pm 1,\,\,y-1=0)\]\[=(3,\,1)\] and\[(1,\,1)\].
You need to login to perform this action.
You will be redirected in
3 sec
