A) \[\frac{1}{2\sqrt{3}}\]
B) \[\frac{1}{\sqrt{3}}\]
C) \[\frac{\sqrt{5}}{3}\]
D) \[\frac{\sqrt{5}}{6}\]
Correct Answer: C
Solution :
\[4{{x}^{2}}+9{{y}^{2}}=36\]\[\Rightarrow \,\,\frac{{{x}^{2}}}{9}+\frac{{{y}^{2}}}{4}=1\]. Here, \[{{a}^{2}}=9,\,{{b}^{2}}=4\] Now\[{{b}^{2}}={{a}^{2}}(1-{{e}^{2}})\], \\[\frac{4}{9}=1-{{e}^{2}}\] \[\Rightarrow \,e=\frac{\sqrt{5}}{3}\].You need to login to perform this action.
You will be redirected in
3 sec