A) \[{{\tan }^{-1}}\left( \frac{12}{5} \right)\]
B) \[{{\tan }^{-1}}(6\sqrt{5})\]
C) \[{{\tan }^{-1}}\left( \frac{12}{\sqrt{5}} \right)\]
D) \[{{\tan }^{-1}}(12\sqrt{5})\]
Correct Answer: C
Solution :
\[S{{S}_{1}}={{T}^{2}}\] \[\tan \theta =2\frac{\sqrt{{{h}^{2}}-ab}}{a+b},\,a=9\], \[b=-4\]and\[h=-12\].You need to login to perform this action.
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