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JEE Main & Advanced Mathematics Conic Sections Question Bank Ellipse

  • question_answer
    The equation of the tangent to the ellipse \[{{x}^{2}}+16{{y}^{2}}=16\] making an angle of \[{{60}^{o}}\]with x-axis is

    A)            \[\sqrt{3}x-y+7=0\]                   

    B)            \[\sqrt{3}x-y-7=0\]

    C)            \[\sqrt{3}x-y\pm 7=0\]             

    D)            None of these

    Correct Answer: C

    Solution :

               \[m=\tan 60{}^\circ =\sqrt{3}\]. Therefore, equation of tangent is \[y=\sqrt{3}x\pm \sqrt{1+3\cdot 16}\] Þ \[y=\sqrt{3}x\pm 7\].


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