A) \[r>2\]
B) \[2<r<5\]
C) \[r>5\]
D) None of these
Correct Answer: B
Solution :
\[\frac{{{x}^{2}}}{2-r}+\frac{{{y}^{2}}}{r-5}+1=0\]Þ\[\frac{{{x}^{2}}}{r-2}+\frac{{{y}^{2}}}{5-r}=1\] Hence \[r>2\]and \[r<5\]Þ\[2<r<5.\]You need to login to perform this action.
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