A) \[\frac{ax}{\sin \theta }-\frac{by}{\cos \theta }={{a}^{2}}-{{b}^{2}}\]
B) \[\frac{ax}{\sin \theta }-\frac{by}{\cos \theta }={{a}^{2}}+{{b}^{2}}\]
C) \[\frac{ax}{\cos \theta }-\frac{by}{\sin \theta }={{a}^{2}}-{{b}^{2}}\]
D) \[\frac{ax}{\cos \theta }-\frac{by}{\sin \theta }={{a}^{2}}+{{b}^{2}}\]
Correct Answer: C
Solution :
\[ax\sec \theta -by\text{ cosec}\theta ={{a}^{2}}-{{b}^{2}}\]. (See theory for formula of tangent on ellipse at parametric point)
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