A) \[{{10}^{-17}}\]Joule
B) 1 Joule
C) \[7\times {{10}^{-8}}\]Joule
D) \[{{10}^{-24}}\]Joule
Correct Answer: D
Solution :
\[E=\frac{hc}{\lambda }=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{21\times {{10}^{-2}}}\]= \[0.94\times {{10}^{-24}}\approx {{10}^{-24}}J\]You need to login to perform this action.
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