A) \[4\times {{10}^{-6}}\]T
B) \[6\times {{10}^{-8}}\]T
C) \[9\times {{10}^{-9}}\]T
D) \[11\times {{10}^{-11}}\]T
Correct Answer: B
Solution :
\[c=\frac{E}{B}\Rightarrow B=\frac{E}{c}=\frac{18}{3\times {{10}^{8}}}=6\times {{10}^{-8}}T\].
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