A) \[{{E}_{0}}k={{B}_{0}}\omega \]
B) \[{{E}_{0}}\omega ={{B}_{0}}k\]
C) \[{{E}_{0}}{{B}_{0}}=\omega k\]
D) None of these
Correct Answer: A
Solution :
\[\frac{{{E}_{0}}}{{{B}_{0}}}=C.\] also \[k=\frac{2\pi }{\lambda }\] and \[\omega =2\pi \nu \] These relation gives \[{{E}_{0}}K={{B}_{0}}\omega \]
You need to login to perform this action.
You will be redirected in
3 sec
