A) \[\pm A\]
B) Zero
C) \[\pm \frac{A}{2}\]
D) \[\pm \frac{A}{\sqrt{2}}\]
Correct Answer: A
Solution :
P.E.\[=\frac{1}{2}m{{\omega }^{2}}{{x}^{2}}\] It is clear P.E. will be maximum when x will be maximum i.e., at \[x=\pm A\]
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