JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Energy of Simple Harmonic Motion

  • question_answer
    When a mass M is attached to the spring of force constant k, then the spring stretches by l. If the mass oscillates with amplitude l, what will be maximum potential energy stored in the spring                                              [BHU 2002]

    A)            \[\frac{kl}{2}\]                     

    B)            \[2kl\]

    C)            \[\frac{1}{2}Mgl\]              

    D)            Mgl

    Correct Answer: C

    Solution :

               \[Mg=Kl\] Þ \[{{U}_{\max }}=\frac{1}{2}K{{l}^{2}}=\frac{1}{2}mgl\]


You need to login to perform this action.
You will be redirected in 3 sec spinner