A) \[5m/s\]
B) \[15m/s\]
C) \[10m/s\]
D) \[20m/s\]
Correct Answer: C
Solution :
Kinetic energy at mean position, \[{{K}_{max}}=\frac{1}{2}mv_{max}^{2}.\]\[\Rightarrow {{v}_{max}}=\sqrt{\frac{2\,{{K}_{max}}}{m}}\] \[=\sqrt{\frac{2\times 16}{0.32}}\]\[=\sqrt{100}\] \[=10\,m/s.\]
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