A) \[\frac{E}{2}\]
B) \[\frac{3}{4}E\]
C) \[\frac{9}{16}E\]
D) None of these
Correct Answer: C
Solution :
\[E=\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}\]Þ\[\frac{{{E}'}}{E}=\frac{{{{{a}'}}^{2}}}{{{a}^{2}}}\]Þ\[\frac{{{E}'}}{E}=\frac{{{\left( \frac{3}{4}a \right)}^{2}}}{{{a}^{2}}}\] \[\left( \because {a}'=\frac{3}{4}a \right)\] Þ\[{E}'=\frac{9}{16}E\]You need to login to perform this action.
You will be redirected in
3 sec