A) \[\sqrt{E}=\sqrt{{{E}_{1}}}-\sqrt{{{E}_{2}}}\]
B) \[\sqrt{E}=\sqrt{{{E}_{1}}}+\sqrt{{{E}_{2}}}\]
C) \[E={{E}_{1}}+{{E}_{2}}\]
D) \[E={{E}_{1}}+{{E}_{2}}\]
Correct Answer: B
Solution :
\[{{E}_{1}}=\frac{1}{2}K{{x}^{2}}\Rightarrow x=\sqrt{\frac{2{{E}_{1}}}{K}}\], \[{{E}_{2}}=\frac{1}{2}K{{y}^{2}}\Rightarrow y=\sqrt{\frac{2{{E}_{2}}}{K}}\] and \[E=\frac{1}{2}K{{(x+y)}^{2}}\Rightarrow x+y=\sqrt{\frac{2E}{K}}\] \[\Rightarrow \sqrt{\frac{2{{E}_{1}}}{K}}+\sqrt{\frac{2{{E}_{2}}}{K}}=\sqrt{\frac{2E}{K}}\]\[\Rightarrow \sqrt{{{E}_{1}}}+\sqrt{{{E}_{2}}}=\sqrt{E}\]You need to login to perform this action.
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