A) 18 J
B) 10 J
C) 12 J
D) 2.5 J
Correct Answer: B
Solution :
\[\frac{\text{Potential energy (}U\text{)}}{\text{Total energy (}E\text{)}}=\frac{\frac{1}{2}m{{\omega }^{2}}{{y}^{2}}}{\frac{1}{2}m{{\omega }^{2}}{{a}^{2}}}=\frac{{{y}^{2}}}{{{a}^{2}}}\] So \[\frac{2.5}{E}=\frac{{{\left( \frac{a}{2} \right)}^{2}}}{{{a}^{2}}}\] Þ \[E=10J\]
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