A) 800 kW
B) 1200 kW
C) 200 kW
D) 400 kW
Correct Answer: C
Solution :
Power of the engine = Frictional force\[\times \]speed \[=\frac{20\times {{10}^{3}}\times 10}{{{10}^{3}}}=200\,kW\]You need to login to perform this action.
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