A) 1/16
B) 1/8
C) 1/4
D) ½
Correct Answer: B
Solution :
\[{{G}_{1}}={{G}_{2}},\] \[{{d}_{1}}={{d}_{2}},\] \[{{D}_{1}}=2.5\,\,cm,\] \[{{D}_{1}}=1.25\,\,cm,\] \[{{n}_{1}}={{n}_{2}}=n,\] Spring constant, \[k=\frac{G{{d}^{4}}}{8{{D}^{3}}n}\] G, d and n being value \[k\propto \frac{1}{{{D}^{3}}}\] \[\frac{{{k}_{1}}}{{{k}_{2}}}={{\left( \frac{{{D}_{2}}}{{{D}_{1}}} \right)}^{3}}={{\left( \frac{1.25}{2.5} \right)}^{3}}=\frac{1}{8}\]You need to login to perform this action.
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