A) 80 N
B) 100 N
C) 200 N
D) 300 N
Correct Answer: A
Solution :
\[200a/g={{W}_{2}}\,\sin 45{}^\circ -T=100\sqrt{2}-T\] \[100a/g=T-{{W}_{1}}\,\sin 30{}^\circ =T-50\] Comparing, we get T=80 NYou need to login to perform this action.
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