A) Three times its initial value
B) Four times its initial value
C) Twice the initial value
D) Unchanged
Correct Answer: C
Solution :
\[{{E}_{1}}=\frac{1}{2}mv_{2}^{1},\] \[{{E}_{2}}=\frac{1}{2}mv_{2}^{2}\] \[{{v}_{2}}=2{{v}_{1}}\] \[m{{v}_{2}}=2m{{v}_{1}}\]
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