A) 800 J
B) 1600 J
C) 3200 J
D) 6400 J
Correct Answer: A
Solution :
\[\delta =1-0.6=0.4\,\,m\] Work done \[=\frac{1}{2}\,k\delta =\frac{1}{2}\times 10\times \frac{{{400}^{2}}}{{{10}^{3}}}=800\,J\]
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