A) \[\frac{{{d}_{2}}+{{d}_{2}}}{2}\]
B) \[\sqrt{{{d}_{1}}{{d}_{2}}}\]
C) \[\sqrt{\frac{{{d}_{1}}{{d}_{2}}}{2}}\]
D) \[\sqrt{\frac{{{d}_{1}}+{{d}_{2}}}{2}}\]
Correct Answer: B
Solution :
\[\frac{4Pl}{\pi E{{d}_{1}}{{d}_{2}}}=\frac{4Pl}{\pi E{{d}^{2}}}\] \[\therefore \,\,d=\sqrt{{{d}_{1}}{{d}_{2}}}\]You need to login to perform this action.
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