A) \[ax+by+1=0\], \[x+y=0\]
B) \[ax+by-1=0\], \[x+y=0\]
C) \[ax+by+1=0\], \[x-y=0\]
D) None of these
Correct Answer: A
Solution :
Equation \[a{{x}^{2}}+(a+b)xy+b{{y}^{2}}+x+y=0\] can be written as\[(ax+by+1)(x+y)=0\].You need to login to perform this action.
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