A) \[\pm \,3\]
B) \[\pm \,\frac{3}{2}\]
C) \[\pm \,2\]
D) \[\pm \,1\]
Correct Answer: A
Solution :
Applying the condition, \[4\lambda {{h}^{2}}=ab{{(1+\lambda )}^{2}}\] Here\[\lambda =2\], therefore \[4\times 2\times {{\left( \frac{h}{2} \right)}^{2}}=1\times 2{{(1+2)}^{2}}\Rightarrow {{h}^{2}}=9\Rightarrow h=\pm 3\].You need to login to perform this action.
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