A) \[2x+7y+3=0\]
B) \[2x-7y+3=0\]
C) \[2x+7y-3=0\]
D) \[2x-7y-3=0\]
Correct Answer: D
Solution :
Given two lines are \[x-6y=0\] and \[x-y=0\]. We know \[\frac{0+{{x}_{1}}+{{x}_{2}}}{3}=1\] \[\Rightarrow {{x}_{1}}+{{x}_{2}}=3\] .....(i) and \[{{y}_{1}}+{{y}_{2}}=0\] .....(ii) Also \[{{x}_{1}}-6{{y}_{1}}=0\] .....(iii) \[{{x}_{2}}-{{y}_{2}}=0\] .....(iv) [Since the point (x1,y1) and \[({{x}_{2}},{{y}_{2}})\]lies on the lines AB and AC respectively] Now on solving, the coordinates of B and C are \[\left( \frac{18}{5},\frac{3}{5} \right)\]and \[\left( \frac{-3}{5},\frac{-3}{5} \right)\]respectively. Hence the equation of third side i.e., BC is \[2x-7y-3=0\].You need to login to perform this action.
You will be redirected in
3 sec