A) 4
B) 3
C) 2
D) None of these
Correct Answer: C
Solution :
We know that \[{{m}_{1}}-{{m}_{2}}=\sqrt{{{({{m}_{1}}+{{m}_{2}})}^{2}}-4{{m}_{1}}{{m}_{2}}}\] \[=\sqrt{{{\left( \frac{2\tan \theta }{{{\sin }^{2}}\theta } \right)}^{2}}-4\left( \frac{{{\sec }^{2}}\theta -{{\sin }^{2}}\theta }{{{\sin }^{2}}\theta } \right)}\] \[=\sqrt{\frac{4{{\tan }^{2}}\theta }{{{\sin }^{4}}\theta }-4({{\sec }^{2}}\theta \,\text{cose}{{\text{c}}^{\text{2}}}\theta -1)}=2\].You need to login to perform this action.
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