A) \[5{{x}^{2}}+5{{y}^{2}}-10x+30y+49=0\]
B) \[5{{x}^{2}}+5{{y}^{2}}+10x-30y+49=0\]
C) \[5{{x}^{2}}+5{{y}^{2}}-10x+30y-49=0\]
D) None of these
Correct Answer: A
Solution :
Radius of circle is \[\left| \frac{2+3-4}{\sqrt{5}} \right|\ =\frac{1}{\sqrt{5}}\] Therefore, equation is \[{{(x-1)}^{2}}+{{(y+3)}^{2}}=\frac{1}{5}\] or \[{{x}^{2}}+{{y}^{2}}-2x+6y+1+9=\frac{1}{5}\] or \[5{{x}^{2}}+5{{y}^{2}}-10x+30y+49=0\].
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