JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Equations of circle, Geometrical problems regarding circle

  • question_answer
    The circle \[{{x}^{2}}+{{y}^{2}}-8x+4y+4=0\]touches  [Karnataka CET 1999, 2004; Pb. CET 2000]

    A)            x-axis only                               

    B)            y- axis only

    C)            Both x and y- axis                   

    D)            Does not touch any axis

    Correct Answer: B

    Solution :

               The given equation can be written as\[{{(x-4)}^{2}}+{{(y+2)}^{2}}={{4}^{2}}\]. We know that the standard equation of the circle with centre (h, k) is \[{{(x-h)}^{2}}+{{(y-k)}^{2}}={{r}^{2}}.\] Comparing the given equation with the standard equation, we get centre º \[(4,\,-2)\] and radius = 4. Since co-ordinates of the centre of the circle are\[(4,\,-2)\], therefore the given circle touches y-axis only.


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