A) 4
B) 6
C) 20
D) \[\sqrt{20}\]
Correct Answer: D
Solution :
Given, diameters of the circles are \[x+y=6\]and\[x+2y=4\]. We know that the intersection point of the diameters is called centre of the circle. \[\therefore \] Centre \[\equiv (8,\,-2)\] Since the circle is passing through the point (6, 2) Hence the distance between the centre (8, ? 2) and point (6, 2) will be the radius of the circle. \[\therefore \] Radius of the circle = \[\sqrt{{{(6-8)}^{2}}+{{(2+2)}^{2}}}=\sqrt{4+16}=\sqrt{20}\].
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