A) \[(2,\,0),(-3,\,0)\]
B) \[(3,\,0),(4,\,0)\]
C) \[(1,\,0),(-1,\,0)\]
D) \[(1,\,0),(2,\,0)\]
Correct Answer: D
Solution :
Given, equation of circle is \[{{x}^{2}}+{{y}^{2}}-3x-4y+2=0\] and it cuts the x-axis. \[\therefore \]\[{{x}^{2}}+0-3x+2=0\] or\[{{x}^{2}}-3x+2=0\] or \[(x-1)\,(x-2)=0\] or \[x=1,\,2.\] Therefore the points are (1,0) and (2, 0).You need to login to perform this action.
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