JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Equations of circle, Geometrical problems regarding circle

  • question_answer
    Centre of circle \[(x-{{x}_{1}})(x-{{x}_{2}})\] \[+(y-{{y}_{1}})(y-{{y}_{2}})\] \[=0\] is

    A)            \[\left( \frac{{{x}_{1}}+{{y}_{1}}}{2},\ \frac{{{x}_{2}}+{{y}_{2}}}{2} \right)\]      

    B)            \[\left( \frac{{{x}_{1}}-{{y}_{1}}}{2},\ \frac{{{x}_{2}}-{{y}_{2}}}{2} \right)\]

    C)            \[\left( \frac{{{x}_{1}}+{{x}_{2}}}{2},\ \frac{{{y}_{1}}+{{y}_{2}}}{2} \right)\]      

    D)            \[\left( \frac{{{x}_{1}}-{{x}_{2}}}{2},\ \frac{{{y}_{1}}-{{y}_{2}}}{2} \right)\]

    Correct Answer: C

    Solution :

               \[({{x}_{1}},\ {{y}_{1}})\] and\[({{x}_{2}},\ {{y}_{2}})\]are extreme points of diameter. Hence centre is \[\left( \frac{{{x}_{1}}+{{x}_{2}}}{2},\ \frac{{{y}_{1}}+{{y}_{2}}}{2} \right)\].


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