A) \[{{x}^{2}}+{{y}^{2}}+6x+8y+1=0\]
B) \[{{x}^{2}}+{{y}^{2}}-6x-8y=0\]
C) \[{{x}^{2}}+{{y}^{2}}+3x+4y=0\]
D) \[{{x}^{2}}+{{y}^{2}}-3x-4y=0\]
Correct Answer: D
Solution :
Obviously the centre of the circle is \[\left( \frac{3}{2},\ 2 \right)\]. Therefore, the equation of circle is \[{{\left( x-\frac{3}{2} \right)}^{2}}+{{(y-2)}^{2}}={{\left( \frac{5}{2} \right)}^{2}}\Rightarrow {{x}^{2}}+{{y}^{2}}-3x-4y=0\].
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