A) \[{{x}^{2}}+{{y}^{2}}+4x+4y-5=0\]
B) \[{{x}^{2}}+{{y}^{2}}-4x-4y-5=0\]
C) \[{{x}^{2}}+{{y}^{2}}-4x=13\]
D) \[{{x}^{2}}+{{y}^{2}}-4x-4y+5=0\]
Correct Answer: B
Solution :
Centre (2, 2) and \[R=\sqrt{{{(4-2)}^{2}}+{{(5-2)}^{2}}}=\sqrt{13}\] Hence required equation is \[{{x}^{2}}+{{y}^{2}}-4x-4y-5=0\] .
You need to login to perform this action.
You will be redirected in
3 sec
